∫etan⁡−1x(1+x2)[(sec⁡−11+x2)2+cos⁡−1(1−x21+x2)]dx\int \frac{e^{\tan^{-1} x}}{(1+x^2)} \left[ (\sec^{-1} \sqrt{1+x^2})^2 + \cos^{-1} \left( \frac{1-x^2}{1+x^2} \right) \right] dx…

Mathematics

Problem

∫etan⁡−1x(1+x2)[(sec⁡−11+x2)2+cos⁡−1(1−x21+x2)]dx\int \frac{e^{\tan^{-1} x}}{(1+x^2)} \left[ (\sec^{-1} \sqrt{1+x^2})^2 + \cos^{-1} \left( \frac{1-x^2}{1+x^2} \right) \right] dx , (x>0x > 0) is equal to a. etan⁡−1x⋅tan⁡−1x+Ce^{\tan^{-1} x} \cdot \tan^{-1} x + C b. etan⁡−1x⋅(tan⁡−1x)22+C\frac{e^{\tan^{-1} x} \cdot (\tan^{-1} x)^2}{2} + C c. etan⁡−1x⋅(sec⁡−1(1+x2))2+Ce^{\tan^{-1} x} \cdot (\sec^{-1}(\sqrt{1+x^2}))^2 + C d. etan⁡−1x⋅(csc⁡−1(1+x2))2+Ce^{\tan^{-1} x} \cdot (\csc^{-1}(\sqrt{1+x^2}))^2 + C

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