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Mathematics
Problem
The value of
∫
0
4
(
y
2
−
4
y
+
5
)
sin
(
y
−
2
)
(
2
y
2
−
8
y
+
1
)
d
y
\int_{0}^{4} \frac{(y^2 - 4y + 5)\sin(y - 2)}{(2y^2 - 8y + 1)}\,dy
∫
0
4
(
2
y
2
−
8
y
+
1
)
(
y
2
−
4
y
+
5
)
s
i
n
(
y
−
2
)
d
y
is a. 0 b. 2 c. -2 d. None of these
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