If A=[cos⁡θsin⁡θ−sin⁡θcos⁡θ]A = \begin{bmatrix} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \end{bmatrix}…

Problem

If A=[cos⁡θsin⁡θ−sin⁡θcos⁡θ]A = \begin{bmatrix} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \end{bmatrix} , then A2=IA^2 = I is true for a. θ=0\theta = 0 b. θ=π4\theta = \frac{\pi}{4} c. θ=π2\theta = \frac{\pi}{2} d. None of these

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