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Mathematics
Problem
The orthogonal projection
A
′
A'
A
′
of the point
A
A
A
with position vector
(
1
,
2
,
3
)
(1, 2, 3)
(
1
,
2
,
3
)
on the plane
3
x
−
y
+
4
z
=
0
3x - y + 4z = 0
3
x
−
y
+
4
z
=
0
is a.
(
−
1
,
3
,
−
1
)
(-1, 3, -1)
(
−
1
,
3
,
−
1
)
b.
(
−
1
2
,
5
2
,
1
)
\left(-\frac{1}{2}, \frac{5}{2}, 1\right)
(
−
2
1
,
2
5
,
1
)
c.
(
1
2
,
−
5
2
,
−
1
)
\left(\frac{1}{2}, -\frac{5}{2}, -1\right)
(
2
1
,
−
2
5
,
−
1
)
d.
(
6
,
−
7
,
−
5
)
(6, -7, -5)
(
6
,
−
7
,
−
5
)
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