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Mathematics
Mathematics
Problem
∫
1
−
7
cos
2
x
sin
7
x
cos
2
x
d
x
=
f
(
x
)
(
sin
x
)
7
+
C
\int \frac{1 - 7 \cos^2 x}{\sin^7 x \cos^2 x} dx = \frac{f(x)}{(\sin x)^7} + C
∫
s
i
n
7
x
c
o
s
2
x
1
−
7
c
o
s
2
x
d
x
=
(
s
i
n
x
)
7
f
(
x
)
+
C
, then
f
(
x
)
f(x)
f
(
x
)
is equal to a.
sin
x
\sin x
sin
x
b.
cos
x
\cos x
cos
x
c.
tan
x
\tan x
tan
x
d.
cot
x
\cot x
cot
x
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