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Mathematics
Mathematics
Problem
Find the value of
a
>
0
a > 0
a
>
0
such that
∫
0
a
4
x
x
2
+
3
d
x
=
ln
16
\int_{0}^{a} \frac{4x}{x^2 + 3} dx = \ln 16
∫
0
a
x
2
+
3
4
x
d
x
=
ln
16
.
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