Problem

Problem

The base of a triangle is divided into three equal parts. If θ1,θ2,θ3\theta_1, \theta_2, \theta_3 be the angles subtended by these parts at the vertex, then prove that (cot⁡θ1+cot⁡θ2)(cot⁡θ2+cot⁡θ3)=4csc⁡2θ2(\cot \theta_1 + \cot \theta_2)(\cot \theta_2 + \cot \theta_3) = 4 \csc^2 \theta_2

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