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Problems
If
y
=
tan
−
1
(
log
(
e
/
x
2
)
log
(
e
x
2
)
)
+
tan
−
1
(
3
+
2
log
x
1
−
6
log
x
)
y = \tan^{-1} \left( \frac{\log(e/x^2)}{\log(ex^2)} \right) + \tan^{-1} \left( \frac{3+2\log x}{1-6\log x} \right)
y
=
tan
−
1
(
l
o
g
(
e
x
2
)
l
o
g
(
e
/
x
2
)
)
+
tan
−
1
(
1
−
6
l
o
g
x
3
+
2
l
o
g
x
)
…
Mathematics
Problem
If
y
=
tan
−
1
(
log
(
e
/
x
2
)
log
(
e
x
2
)
)
+
tan
−
1
(
3
+
2
log
x
1
−
6
log
x
)
y = \tan^{-1} \left( \frac{\log(e/x^2)}{\log(ex^2)} \right) + \tan^{-1} \left( \frac{3+2\log x}{1-6\log x} \right)
y
=
tan
−
1
(
l
o
g
(
e
x
2
)
l
o
g
(
e
/
x
2
)
)
+
tan
−
1
(
1
−
6
l
o
g
x
3
+
2
l
o
g
x
)
, then
d
2
y
d
x
2
\frac{d^2 y}{dx^2}
d
x
2
d
2
y
is (a) 2 (b) 1 (c) 0 (d) -1
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