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Mathematics
Problem
If the straight line
a
x
+
b
y
=
2
ax + by = 2
a
x
+
b
y
=
2
;
a
,
b
≠
0
a, b \neq 0
a
,
b
=
0
touches the circle
x
2
+
y
2
−
2
x
=
3
x^2 + y^2 - 2x = 3
x
2
+
y
2
−
2
x
=
3
and is normal to the circle
x
2
+
y
2
−
4
y
=
6
x^2 + y^2 - 4y = 6
x
2
+
y
2
−
4
y
=
6
, then the values of
a
a
a
and
b
b
b
are respectively (A) 1, -1 (B) 1, 2 (C)
−
4
3
-\frac{4}{3}
−
3
4
, 1 (D) 2, 1
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