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Mathematics
Mathematics
Problem
If
y
=
(
x
+
x
2
+
1
)
m
y = (x + \sqrt{x^2 + 1})^m
y
=
(
x
+
x
2
+
1
)
m
, then prove that
(
x
2
+
1
)
y
′
′
+
x
y
′
−
m
2
y
=
0
(x^2 + 1)y'' + xy' - m^2 y = 0
(
x
2
+
1
)
y
′′
+
x
y
′
−
m
2
y
=
0
.
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