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Problem The mirror image of the curve arg ( z + i z − 1 ) = π 4 \arg\left(\frac{z+i}{z-1}\right) = \frac{\pi}{4} arg ( z − 1 z + i ) = 4 π i = − 1 i = \sqrt{-1} i = − 1 x − y = 0 x - y = 0 x − y = 0 arg ( z + i z + 1 ) = π 4 \arg\left(\frac{z+i}{z+1}\right) = \frac{\pi}{4} arg ( z + 1 z + i ) = 4 π arg ( z + 1 z − i ) = π 4 \arg\left(\frac{z+1}{z-i}\right) = \frac{\pi}{4} arg ( z − i z + 1 ) = 4 π arg ( z − i z + 1 ) = π 4 \arg\left(\frac{z-i}{z+1}\right) = \frac{\pi}{4} arg ( z + 1 z − i ) = 4 π arg ( z + i z − 1 ) = π 4 \arg\left(\frac{z+i}{z-1}\right) = \frac{\pi}{4} arg ( z − 1 z + i ) = 4 π Browse the problem library