Chemistry

Problem

The resistance of

0.05\text{ N}

solution of an electrolyte

A_aB_b

was found to be

210\text{ ohm}

300\text{ K}

. If cell constant is

0.88\text{ cm}^{-1}

, the molar conductivity is in

\text{S m}^2\text{mol}^{-1}

is : a.

83.81 \times (a+b)

83.81 \times (a+b) \times 10^{-4}

83.81 \times (a \cdot b)

83.81 \times (a \cdot b) \times 10^{-4}