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Problem
Problem
Find the number of roots of the equation
16
sec
3
θ
−
12
tan
2
θ
−
4
sec
θ
=
9
16\sec^3 \theta - 12\tan^2 \theta - 4\sec \theta = 9
16
sec
3
θ
−
12
tan
2
θ
−
4
sec
θ
=
9
in interval
(
−
π
,
π
)
(-\pi, \pi)
(
−
π
,
π
)
.
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