When photon of energy 4.25 eV strikes the surface, the ejected electron has maximum kinetic energy TA expressed in eV and de Broglie wavelength λA. The maximum kinetic energy of photoelectrons liberated by another metal B by photons of 4.70 eV is TB (TB=TA−1.5 eV). If de Broglie wavelength of the electron is λB (λB=2λA), then which is not correct?
a. work function of A is 2.25 eV
b. TB=0.5 eV
c. work function of B is 1.20 eV
d. TA=2.0 eV