Problem

Problem

If the equation (1+m)x2−2(1+3m)x+(1+8m)=0(1+m)x^2 - 2(1+3m)x + (1+8m) = 0, where m∈R∖{−1}m \in \mathbb{R} \setminus \{-1\}, has at least one root is negative, then a. m∈(−∞,−1)m \in (-\infty, -1) b. m∈(−18,∞)m \in \left(-\frac{1}{8}, \infty\right) c. m∈(−1,−18)m \in \left(-1, -\frac{1}{8}\right) d. m∈Rm \in \mathbb{R}

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