JEE Advanced 2015 Paper 1 Chemistry Q7

Chemistry · Electrochemistry · Free Energy & Chemical Equilibrium

Problem

All the energy released from the reaction

X\rightarrow Y

\Delta_rG^\circ=-193\,\mathrm{kJ\,mol^{-1}}

is used for oxidizing

\ce{M+}

\ce{M+ -> M^{3+} + 2e^-}

E^\circ=-0.25\,\mathrm V

. Under standard conditions, the number of moles of

\ce{M+}

oxidized when one mole of

X

is converted to

Y

is. [

F=96500\,\mathrm{C\,mol^{-1}}

]