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Mathematics
Problem
In triangle ABC, the value of
r
(
1
+
cos
C
)
r
1
+
r
2
\frac{r(1+\cos C)}{r_1+r_2}
r
1
+
r
2
r
(
1
+
c
o
s
C
)
is equal to (where notations have their usual meaning) (a)
2
sin
A
2
sin
B
2
sin
C
2
2 \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2}
2
sin
2
A
sin
2
B
sin
2
C
(b)
2
cos
A
2
csc
B
2
csc
C
2
2 \cos \frac{A}{2} \csc \frac{B}{2} \csc \frac{C}{2}
2
cos
2
A
csc
2
B
csc
2
C
(c)
2
cos
A
2
cos
B
2
cos
C
2
2 \cos \frac{A}{2} \cos \frac{B}{2} \cos \frac{C}{2}
2
cos
2
A
cos
2
B
cos
2
C
(d)
2
sec
A
2
sec
B
2
sec
C
2
2 \sec \frac{A}{2} \sec \frac{B}{2} \sec \frac{C}{2}
2
sec
2
A
sec
2
B
sec
2
C
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