Problem

Problem

If ΔPQR\Delta PQR is a triangle of area Δ\Delta with a=2,b=72a = 2, b = \frac{7}{2} and c=52c = \frac{5}{2} , where a,ba, b and cc are the lengths of the sides of the triangle opposite to the angles at P,QP, Q and RR , respectively. Then, 2sin⁡P−sin⁡2P2sin⁡P+sin⁡2P\frac{2 \sin P - \sin 2P}{2 \sin P + \sin 2P} equals a. 34Δ\frac{3}{4\Delta} b. 454Δ\frac{45}{4\Delta} c. (34Δ)2\left(\frac{3}{4\Delta}\right)^2 d. (454Δ)5\left(\frac{45}{4\Delta}\right)^5

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