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Problem
Problem
If
Δ
P
Q
R
\Delta PQR
Δ
P
QR
is a triangle of area
Δ
\Delta
Δ
with
a
=
2
,
b
=
7
2
a = 2, b = \frac{7}{2}
a
=
2
,
b
=
2
7
and
c
=
5
2
c = \frac{5}{2}
c
=
2
5
, where
a
,
b
a, b
a
,
b
and
c
c
c
are the lengths of the sides of the triangle opposite to the angles at
P
,
Q
P, Q
P
,
Q
and
R
R
R
, respectively. Then,
2
sin
P
−
sin
2
P
2
sin
P
+
sin
2
P
\frac{2 \sin P - \sin 2P}{2 \sin P + \sin 2P}
2
s
i
n
P
+
s
i
n
2
P
2
s
i
n
P
−
s
i
n
2
P
equals a.
3
4
Δ
\frac{3}{4\Delta}
4Δ
3
b.
45
4
Δ
\frac{45}{4\Delta}
4Δ
45
c.
(
3
4
Δ
)
2
\left(\frac{3}{4\Delta}\right)^2
(
4Δ
3
)
2
d.
(
45
4
Δ
)
5
\left(\frac{45}{4\Delta}\right)^5
(
4Δ
45
)
5
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