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Mathematics
Mathematics
Problem
If
f
(
x
)
=
{
A
+
B
x
2
x
<
1
3
A
x
−
B
+
2
x
≥
1
f(x)=\begin{cases}A+Bx^2 & x<1\\3Ax-B+2 & x\ge 1\end{cases}
f
(
x
)
=
{
A
+
B
x
2
3
A
x
−
B
+
2
x
<
1
x
≥
1
, then find
A
A
A
and
B
B
B
so that
f
(
x
)
f(x)
f
(
x
)
become differentiable at
x
=
1
x=1
x
=
1
.
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