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Mathematics
Mathematics
Problem
3. If the lines
x
−
1
−
3
=
y
−
2
2
k
=
z
−
3
2
\frac{x-1}{-3}=\frac{y-2}{2 k}=\frac{z-3}{2}
−
3
x
−
1
=
2
k
y
−
2
=
2
z
−
3
and
x
−
1
3
k
=
y
−
1
1
=
z
−
6
−
5
\frac{x-1}{3 k}=\frac{y-1}{1}=\frac{z-6}{-5}
3
k
x
−
1
=
1
y
−
1
=
−
5
z
−
6
are perpendicular, find the value of
k
k
k
.
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