If f(x)={2x2+2x2,0<∣x∣≤23,x>2f(x) = \begin{cases} 2x^2 + \frac{2}{x^2}, & 0 < |x| \le 2 \\ 3, & x > 2 \end{cases}…

Problem

If f(x)={2x2+2x2,0<∣x∣≤23,x>2f(x) = \begin{cases} 2x^2 + \frac{2}{x^2}, & 0 < |x| \le 2 \\ 3, & x > 2 \end{cases} , then a. x=1,−1x = 1, -1 are the points of global minima b. x=1,−1x = 1, -1 are the points of local minima c. x=0x = 0 is the point of local minima d. None of the above

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