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Mathematics
Mathematics
Problem
Find
h
′
(
θ
)
h'(\theta)
h
′
(
θ
)
in simplest form for
h
(
θ
)
=
cos
2
θ
sin
θ
h(\theta)=\dfrac{\cos 2\theta}{\sin \theta}
h
(
θ
)
=
sin
θ
cos
2
θ
. Express your answer using only powers of
sin
θ
\sin\theta
sin
θ
and
cos
θ
\cos\theta
cos
θ
(no other trigonometric functions).
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