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Physics
Physics
Problem
A 60 kg geologist is working at the bottom of a mine shaft 800 m deep. Answer the following: a. (a) Calculate the value of
g
g
g
at that depth. Take
g
=
9.80
m s
−
2
g=9.80\,\text{m s}^{-2}
g
=
9.80
m s
−
2
at the surface and
R
E
=
6.4
×
10
6
m
R_{\rm E}=6.4\times10^6\,\text{m}
R
E
=
6.4
×
1
0
6
m
. b. (b) Determine the geologist’s weight at that depth.
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