Physics

Physics

Problem

A particle executing SHM is described by

x = A\cos(2 t + \phi)

, where

x

is in metres and

t

in seconds. If at

t=0

the particle has displacement

0.0866\,\text{m}

and velocity

0.10\,\text{m s}^{-1}

, the correct equation of motion is a)

x = 0.10\,\cos\!\left(2 t + \dfrac{\pi}{6}\right)

b)

x = 0.05\,\cos\!\left(2 t - \dfrac{\pi}{6}\right)

c)

x = 0.10\,\cos\!\left(2 t - \dfrac{\pi}{6}\right)

d)

x = 0.0866\,\cos\!\left(2 t\right)

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