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Mathematics
Problem
If 2 and 6 are the roots of the equation
a
x
2
+
b
x
+
1
=
0
ax^2 + bx + 1 = 0
a
x
2
+
b
x
+
1
=
0
, then the quadratic equation, whose roots are
1
2
a
+
b
\frac{1}{2a+b}
2
a
+
b
1
and
1
6
a
+
b
\frac{1}{6a+b}
6
a
+
b
1
, is: (A)
2
x
2
+
11
x
+
12
=
0
2x^2 + 11x + 12 = 0
2
x
2
+
11
x
+
12
=
0
(B)
4
x
2
+
14
x
+
12
=
0
4x^2 + 14x + 12 = 0
4
x
2
+
14
x
+
12
=
0
(C)
x
2
+
10
x
+
16
=
0
x^2 + 10x + 16 = 0
x
2
+
10
x
+
16
=
0
(D)
x
2
+
8
x
+
12
=
0
x^2 + 8x + 12 = 0
x
2
+
8
x
+
12
=
0
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