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Problem For g ( x ) = e 5 x x 2 + 1 g(x)=\dfrac{e^{5x}}{x^{2}+1} g ( x ) = x 2 + 1 e 5 x g ′ ( x ) g'(x) g ′ ( x ) 5 e 5 x ( x 2 + 1 ) 2 − 2 x e 5 x x 2 + 1 \displaystyle \frac{5e^{5x}}{(x^{2}+1)^{2}}-\frac{2xe^{5x}}{x^{2}+1} ( x 2 + 1 ) 2 5 e 5 x − x 2 + 1 2 x e 5 x 5 e 5 x x 2 + 1 + 2 x e 5 x ( x 2 + 1 ) 2 \displaystyle \frac{5e^{5x}}{x^{2}+1}+\frac{2xe^{5x}}{(x^{2}+1)^{2}} x 2 + 1 5 e 5 x + ( x 2 + 1 ) 2 2 x e 5 x e 5 x [ 5 ( x 2 + 1 ) − 2 x ] ( x 2 + 1 ) 2 \displaystyle \frac{e^{5x}\bigl[5(x^{2}+1)-2x\bigr]}{(x^{2}+1)^{2}} ( x 2 + 1 ) 2 e 5 x [ 5 ( x 2 + 1 ) − 2 x ] e 5 x [ ( x 2 + 1 ) − 2 x ] ( x 2 + 1 ) 2 \displaystyle \frac{e^{5x}\bigl[(x^{2}+1)-2x\bigr]}{(x^{2}+1)^{2}} ( x 2 + 1 ) 2 e 5 x [ ( x 2 + 1 ) − 2 x ] Browse the problem library