Mathematics

Mathematics

Problem

If f(x)={x}g(x)[x]g(x)f(x) = \frac{\{x\}g(x)}{[x]g(x)} is a periodic function with period 14\frac{1}{4} , where g(x)g(x) is a differentiable function, then (where {⋅}\{\cdot\} denotes fractional part of xx ). a. g′(x)g'(x) has exactly three roots in (14,54)(\frac{1}{4}, \frac{5}{4}) b. g(x)=0g(x) = 0 at x=k4x = \frac{k}{4} , where k∈Ik \in \mathbb{I} c. g(x)g(x) must be non-zero function d. g(x)g(x) must be periodic function

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