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Mathematics
Mathematics
Problem
Let
θ
=
tan
−
1
(
tan
5
π
4
)
\theta = \tan^{-1}\left(\tan \frac{5\pi}{4}\right)
θ
=
tan
−
1
(
tan
4
5
π
)
and
ϕ
=
tan
−
1
(
−
tan
2
π
3
)
\phi = \tan^{-1}\left(-\tan \frac{2\pi}{3}\right)
ϕ
=
tan
−
1
(
−
tan
3
2
π
)
then a.
θ
>
ϕ
\theta > \phi
θ
>
ϕ
b.
4
θ
−
3
ϕ
=
0
4\theta - 3\phi = 0
4
θ
−
3
ϕ
=
0
c.
θ
+
ϕ
=
7
π
12
\theta + \phi = \frac{7\pi}{12}
θ
+
ϕ
=
12
7
π
d. None of these
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