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Mathematics
Problem
Let
x
=
t
2
+
1
x=t^{2}+1
x
=
t
2
+
1
and
y
=
t
3
−
t
y=t^{3}-t
y
=
t
3
−
t
. Calculate
d
2
y
d
x
2
\dfrac{d^{2}y}{dx^{2}}
d
x
2
d
2
y
at
t
=
1
t=1
t
=
1
. a)
2
2
2
b)
1
2
\dfrac{1}{2}
2
1
c)
1
1
1
d)
−
1
-1
−
1
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