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Mathematics
Mathematics
Problem
Given
sin
θ
=
3
5
\sin \theta = \dfrac{3}{5}
sin
θ
=
5
3
and
cos
θ
=
4
5
\cos \theta = \dfrac{4}{5}
cos
θ
=
5
4
, find
tan
θ
\tan \theta
tan
θ
. a)
4
3
\dfrac{4}{3}
3
4
b)
3
4
\dfrac{3}{4}
4
3
c)
7
5
\dfrac{7}{5}
5
7
d)
12
25
\dfrac{12}{25}
25
12
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