Physics

Physics

Problem

A parallel plate capacitor with plate area AA and separation dd is charged to a potential difference V0=20 VV_{0} = 20\,\text{V} and then disconnected from the battery. The initial capacitance is C0=10 μFC_{0} = 10\,\mu\text{F}. The plates are then pulled apart to double the separation (2d2d), and the space between them is completely filled with a dielectric material of dielectric constant K=4K = 4. Determine the new potential difference across the plates and the new stored energy.

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