Mathematics

Mathematics

Problem

If ω\omega is the cube root of unity, then ∣1ωω2ωω21ω21ω∣=\begin{vmatrix} 1 & \omega & \omega^2 \\ \omega & \omega^2 & 1 \\ \omega^2 & 1 & \omega \end{vmatrix} = (a) 1 (b) 0 (c) ω\omega (d) ω2\omega^2 (a) 1 (b) 0 (c) ω\omega (d) ω2\omega^2

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