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Problem
Problem
If
cos
x
−
cot
β
sin
x
2
=
3
2
\cos x - \frac{\cot \beta \sin x}{2} = \frac{\sqrt{3}}{2}
cos
x
−
2
c
o
t
β
s
i
n
x
=
2
3
, then the value of
tan
x
2
\tan \frac{x}{2}
tan
2
x
is a.
tan
β
2
−
tan
15
∘
\tan \frac{\beta}{2} - \tan 15^\circ
tan
2
β
−
tan
1
5
∘
b.
tan
β
2
\tan \frac{\beta}{2}
tan
2
β
c.
tan
15
∘
\tan 15^\circ
tan
1
5
∘
d. None of the above
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