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Chemistry
Chemistry
Problem
At 500 K the equilibrium constant for PCl
5
_5
5
(g) ⇌ PCl
3
_3
3
(g) + Cl
2
_2
2
(g) is
K
c
=
1.8
×
10
−
1
K_c = 1.8 \times 10^{-1}
K
c
=
1.8
×
1
0
−
1
. A rigid container initially holds only 0.450 M PCl
5
_5
5
(g) and no products. Calculate the equilibrium concentration (in mol L
−
1
^{-1}
−
1
) of Cl
2
_2
2
(g).
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