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Problem
Problem
Prove that
log
2
24
log
9
2
−
log
2
192
log
12
2
=
3
\frac{\log_2 24}{\log_9 2} - \frac{\log_2 192}{\log_{12} 2} = 3
l
o
g
9
2
l
o
g
2
24
−
l
o
g
12
2
l
o
g
2
192
=
3
.
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