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Mathematics
Mathematics
Problem
Given
sin
θ
=
3
5
\sin\theta = \dfrac{3}{5}
sin
θ
=
5
3
with
θ
\theta
θ
in the first quadrant, find the value of
cos
2
θ
\cos 2\theta
cos
2
θ
. a)
−
7
25
-\dfrac{7}{25}
−
25
7
b)
16
25
\dfrac{16}{25}
25
16
c)
7
25
\dfrac{7}{25}
25
7
d)
24
25
\dfrac{24}{25}
25
24
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