Mathematics

Mathematics

Problem

If xy=yxx^y = y^x , then dydx=\frac{dy}{dx} = (a) y(xlog⁡ey+y)x(ylog⁡ex+x)\frac{y(x \log_e y + y)}{x(y \log_e x + x)} (b) y(xlog⁡ey−y)x(ylog⁡ex−x)\frac{y(x \log_e y - y)}{x(y \log_e x - x)} (c) x(xlog⁡ey−y)y(ylog⁡ex−x)\frac{x(x \log_e y - y)}{y(y \log_e x - x)} (d) x(xlog⁡ey+y)y(ylog⁡ex+x)\frac{x(x \log_e y + y)}{y(y \log_e x + x)}

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