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Mathematics
Problem
Identify the constant
k
k
k
so that
d
(
4
x
2
)
d
x
=
k
x
d
x
,
\frac{d(4x^2)}{dx} = kx\,dx,
d
x
d
(
4
x
2
)
=
k
x
d
x
,
and hence the integral
1
k
(
k
x
θ
(
4
x
2
)
)
d
x
\frac{1}{k}\bigl(kx\,\theta(4x^2)\bigr)dx
k
1
(
k
x
θ
(
4
x
2
)
)
d
x
contains the exact differential of
4
x
2
4x^2
4
x
2
. State the value of
k
k
k
.
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