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JEE Advanced 2013 Paper 2 Chemistry Q5
Chemistry · Chemical Equilibria for Analysis
Problem
The
K
s
p
K_{sp}
K
s
p
of
A
g
X
2
C
r
O
X
4
\ce{Ag2CrO4}
Ag
X
2
CrO
X
4
is
1.1
×
10
−
12
1.1\times10^{-12}
1.1
×
1
0
−
12
at
298
K
298\,\mathrm K
298
K
. The solubility (in
m
o
l
L
−
1
\mathrm{mol\,L^{-1}}
mol
L
−
1
) of
A
g
X
2
C
r
O
X
4
\ce{Ag2CrO4}
Ag
X
2
CrO
X
4
in a
0.1
M
0.1\,\mathrm M
0.1
M
A
g
N
O
X
3
\ce{AgNO3}
AgNO
X
3
solution is
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