Physics

Physics

Problem

A rod of length LL has non-uniform linear mass density given by ρ(x)=a+b(xL)2\rho(x) = a + b\left(\frac{x}{L}\right)^2 , where aa and bb are constants and 0≤x≤L0 \le x \le L . The value of xx for the centre of mass of the rod is at: a. 32(a+b2a+b)L\frac{3}{2}\left(\frac{a+b}{2a+b}\right)L b. 34(2a+b3a+b)L\frac{3}{4}\left(\frac{2a+b}{3a+b}\right)L c. 43(a+b2a+3b)L\frac{4}{3}\left(\frac{a+b}{2a+3b}\right)L d. 32(2a+b3a+b)L\frac{3}{2}\left(\frac{2a+b}{3a+b}\right)L

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