Mathematical Methods in the Physical Sciences · Problem 2.15

FUNCTIONS OF A COMPLEX VARIABLE — Mary Boas

Mathematics — Methods · laplace-equation-finite-plate-insulated

Problem

Consider a finite plate, 10 cm by 30 cm, with two insulated sides, one end at 0∘0^\circ and the other at a given temperature T=f(x)T = f(x). Try f(x)=100∘f(x) = 100^\circ; f(x)=xf(x) = x. You should convince yourself that this problem cannot be done using just the solutions (2.7). To see what is wrong, go back to the differential equations (2.5) and solve them if k=0k = 0. You should find solutions xx, yy, xyxy, and constant [the constant is already contained in (2.7) for k=0k = 0, but the other three solutions are not]. Now go back over each of the problems we have done so far and see why we could ignore these k=0k = 0 solutions; then including the k=0k = 0 solutions, finish the problem of the finite plate with insulated sides. For the case f(x)=xf(x) = x, the answer is: T=16(30−y)−40π2∑odd n1n2sinh⁡3nπsinh⁡nπ10(30−y)cos⁡nπx10.T = \tfrac{1}{6}(30 - y) - \frac{40}{\pi^2} \sum_{\text{odd}\,n} \frac{1}{n^2 \sinh 3n\pi} \sinh \frac{n\pi}{10}(30 - y) \cos \frac{n\pi x}{10}.

Browse the problem library