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Mathematics
Problem
The positions (in meters) of two particles moving along a straight path are given for
t
≥
0
t\ge 0
t
≥
0
by
s
A
(
t
)
=
4
t
+
1
,
s
B
(
t
)
=
3
t
+
10.
s_A(t)=4t+1,\qquad s_B(t)=3t+10.
s
A
(
t
)
=
4
t
+
1
,
s
B
(
t
)
=
3
t
+
10.
At what time do the two particles occupy the same position? a)
t
=
11
s
t=11\text{ s}
t
=
11
s
b) They never occupy the same position. c)
t
≈
1.3
s
t\approx1.3\text{ s}
t
≈
1.3
s
d)
t
=
9
s
t=9\text{ s}
t
=
9
s
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