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Problems
If
∫
cos
x
−
sin
x
+
1
−
x
e
x
+
sin
x
+
x
d
x
=
ln
{
f
(
x
)
}
+
g
(
x
)
+
C
\int \frac{\cos x - \sin x + 1 - x}{e^x + \sin x + x} dx = \ln \{f(x)\} + g(x) + C
∫
e
x
+
s
i
n
x
+
x
c
o
s
x
−
s
i
n
x
+
1
−
x
d
x
=
ln
{
f
(
x
)}
+
g
(
x
)
+
C
,…
Mathematics
Problem
If
∫
cos
x
−
sin
x
+
1
−
x
e
x
+
sin
x
+
x
d
x
=
ln
{
f
(
x
)
}
+
g
(
x
)
+
C
\int \frac{\cos x - \sin x + 1 - x}{e^x + \sin x + x} dx = \ln \{f(x)\} + g(x) + C
∫
e
x
+
s
i
n
x
+
x
c
o
s
x
−
s
i
n
x
+
1
−
x
d
x
=
ln
{
f
(
x
)}
+
g
(
x
)
+
C
, where
C
C
C
is the constant of integrating and
f
(
x
)
f(x)
f
(
x
)
is positive, then
f
(
x
)
+
g
(
x
)
e
x
+
sin
x
\frac{f(x) + g(x)}{e^x + \sin x}
e
x
+
s
i
n
x
f
(
x
)
+
g
(
x
)
is equal to .....
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