Problem

Problem

If g(x)=x2+x−2g(x) = x^2 + x - 2 and 12(g∘f)(x)=2x2−5x+2\frac{1}{2}(g \circ f)(x) = 2x^2 - 5x + 2, then f(x)f(x) is equal to (a) 2x−32x - 3 (b) 2x+32x + 3 (c) 2x2+3x+12x^2 + 3x + 1 (d) 2x2−3x−12x^2 - 3x - 1

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