Introduction to Electrodynamics · Problem 3.48

Potentials — David J. Griffiths

Physics · dipole-field-delta-function

Problem

(a) Using Eq. 3.103, calculate the average electric field of a dipole, over a spherical volume of radius RR, centered at the origin. Do the angular integrals first. [*Note:* You must express r^\hat{\mathbf{r}} and θ^\hat{\boldsymbol{\theta}} in terms of x^\hat{\mathbf{x}}, y^\hat{\mathbf{y}}, and z^\hat{\mathbf{z}} (see back cover) before integrating. If you don't understand why, reread the discussion in Sect. 1.4.1.] Compare your answer with the general theorem (Eq. 3.105). The discrepancy here is related to the fact that the field of a dipole blows up at r=0r = 0. The angular integral is zero, but the radial integral is infinite, so we really don't know what to make of the answer. To resolve this dilemma, let's say that Eq. 3.103 applies outside a tiny sphere of radius ϵ\epsilon—its contribution to EaveE_{\text{ave}} is then unambiguously zero, and the whole answer has to come from the field inside the ϵ\epsilon-sphere. (b) What must the field inside the ϵ\epsilon-sphere be, in order for the general theorem (Eq. 3.105) to hold? [*Hint:* since ϵ\epsilon is arbitrarily small, we're talking about something that is infinite at r=0r = 0 and whose integral over an infinitesimal volume is finite.] [*Answer:* −(p/3ϵ0)δ3(r)-(\mathbf{p}/3\epsilon_0)\delta^3(\mathbf{r})] Evidently, the true field of a dipole is Edip(r)=14πϵ01r3[3(p⋅r^)r^−p]−13ϵ0p δ3(r).\mathbf{E}_{\text{dip}}(\mathbf{r}) = \frac{1}{4\pi\epsilon_0}\frac{1}{r^3}[3(\mathbf{p}\cdot\hat{\mathbf{r}})\hat{\mathbf{r}} - \mathbf{p}] - \frac{1}{3\epsilon_0}\mathbf{p}\,\delta^3(\mathbf{r}).

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