Physics

Physics

Problem

The mass of a miner’s toolbox is 50 kg50\,\text{kg}. Take g=9.8 m s−2g = 9.8\,\text{m\,s}^{-2} and Earth’s radius R=6.4×103 kmR = 6.4 \times 10^{3}\,\text{km}. Calculate its weight when it is lowered to a depth of 4.0×102 km4.0 \times 10^{2}\,\text{km} below the Earth’s surface. Ignore rotational effects. a) 5.2×102 N5.2 \times 10^{2}\,\text{N} b) 4.6×102 N4.6 \times 10^{2}\,\text{N} c) 4.3×102 N4.3 \times 10^{2}\,\text{N} d) 4.9×102 N4.9 \times 10^{2}\,\text{N}

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