Physics

Problem

A particle of mass

m

is projected with a speed

u

from the ground at an angle

\theta = \frac{\pi}{3}

w.r.t. horizontal (x-axis). When it has reached its maximum height, it collides completely inelastically with another particle of the same mass and velocity

u\hat{i}

. The horizontal distance covered by the combined mass before reaching the ground is: [Main 9 Jan. 2020] (a)

\frac{3\sqrt{3}u^2}{8g}

(b)

\frac{3\sqrt{2}u^2}{4g}

(c)

\frac{5u^2}{8g}

(d)

2\sqrt{2}\frac{u^2}{g}

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