Mathematics

Mathematics

Problem

Let the tangents at the points

A(4, -11)

and

B(8, -5)

on the circle

x^2 + y^2 - 3x + 10y - 15 = 0

, intersect at the point

C

. Then, the radius of the circle, whose centre is

C

and the line joining

A

and

B

is its tangent, is equal to (a)

2\sqrt{13}

(b)

\frac{2\sqrt{13}}{3}

(c)

\frac{3\sqrt{3}}{4}

(d)

\sqrt{13}

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