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Mathematics
Mathematics
Problem
The value of
∑
n
=
1
10
(
sin
2
n
π
11
−
cos
2
n
π
11
)
\sum_{n=1}^{10} \left( \sin \frac{2n\pi}{11} - \cos \frac{2n\pi}{11} \right)
∑
n
=
1
10
(
sin
11
2
nπ
−
cos
11
2
nπ
)
is equal to a. 2 b. 1 c. 0 d. -1
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