Problem

Problem

If log⁡5120+(x−3)−2log⁡5(1−5x−3)=−log⁡5(0.2−5x−4)\log_5 120 + (x-3) - 2 \log_5 (1-5^{x-3}) = -\log_5 (0.2 - 5^{x-4}) , then xx is a. 1 b. 2 c. 3 d. 4

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